HBLbits_Verilog Basic_Vector3
The concatenation operator {a,b,c} is used to create larger vectors by concatenating smaller portions of a vector together.
{3'b111, 3'b000} => 6'b111000
{1'b1, 1'b0, 3'b101} => 5'b10101
{4'ha, 4'd10} => 8'b10101010 // 4'ha and 4'd10 are both 4'b1010 in binary
Concatenation needs to know the width of every component (or how would you know the length of the result?). Thus, {1, 2, 3} is illegal and results in the error message: unsized constants are not allowed in concatenations.
The concatenation operator can be used on both the left and right sides of assignments.
input [15:0] in;
output [23:0] out;
assign {out[7:0], out[15:8]} = in; // Swap two bytes. Right side and left side are both 16-bit vectors.
assign out[15:0] = {in[7:0], in[15:8]}; // This is the same thing.
assign out = {in[7:0], in[15:8]}; // This is different. The 16-bit vector on the right is extended to
// match the 24-bit vector on the left, so out[23:16] are zero.
// In the first two examples, out[23:16] are not assigned.
module top_module (
input [4:0] a, b, c, d, e, f,
output [7:0] w, x, y, z );//
// assign { ... } = { ... };
assign {w,x,y,z} = { a, b, c, d, e, f,2'b11 };
endmodule
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