2019年2月12日 星期二

習題1-3-b 已知下列諸點寫出牛頓差除表及i=2到i=5的一元三次方程式

習題1-3-b
已知下列諸點
x        f(x)
=============
1.0      2.72
1.2      3.32
1.4      4.06
1.5      4.48
1.8      6.05
2.0      7.39
寫出牛頓差除表及i=2到i=5的一元三次方程式


'''
/* pr1-3-b.py is for developing the divided-defference
 * table for Newton Interpolation polynomial.
 */
n=6
x        f(x)
=============
1.0      2.72
1.2      3.32
1.4      4.06
1.5      4.48
1.8      6.05
2.0      7.39
=============
'''

n=6
x= [0.0 for i in range(0,n)]     #x [n] 矩陣
f=  [ [0.0 for i in range(n)]  for j in range(n) ]       #[n] * [n] 矩陣
x= [1.0 , 1.2 , 1.4 , 1.5 , 1.8 ,  2.0]
f= [[2.72 , 3.32  , 4.06  ,4.48  , 6.05 , 7.39 ],
      [0.0 ,     0.0   ,0.0  ,0.0 ,0.0 ,0.0  ],
      [0.0 ,     0.0   ,0.0  ,0.0 ,0.0 ,0.0  ],
      [0.0 ,     0.0   ,0.0  ,0.0 ,0.0 ,0.0  ],
      [0.0 ,     0.0   ,0.0  ,0.0 ,0.0 ,0.0  ],
      [0.0 ,     0.0   ,0.0  ,0.0 ,0.0 ,0.0  ]]

print("\nNewton's Divided Interpolation : ")
print("\nEnter the value of n : ",n)
print("\nEnter the value of x[i] and f[i][0] : \n");
print("\tx[i]\t\tf[i][0]");
for i  in range (len(x)) :    
    print(  '\t',round(x[i],4),"\t\t",round( f[0][i],4))
print()

print("\n        Divided Difference Table:")
print("======================================================================"  )

for i in range (1 ,n):
    for j in range (0 , n-i):
        f[i][j]=(f[i-1][j+1]-f[i-1][j]) / (x[i+j]-x[j])

print("i\tx(i)\tf(i)\t\t\tf(i,i+1)\tf(i,i+1.i+2),  ......\n");
for i in range (0 ,n):
    print ("{%d}\t{%2.5f}" %(i,x[i]), end='')
    for j in range (0 , n-i):
        print("\t{%2.5f}" %(f[j][i]) ,end='')

    print("\n")


======= RESTART: H:/2018-09勤益科大數值分析/數值分析/PYTHON/pr1-3-b.py =========

Newton's Divided Interpolation : 

Enter the value of n :  6

Enter the value of x[i] and f[i][0] : 

x[i] f[i][0]
1.0 2.72
1.2 3.32
1.4 4.06
1.5 4.48
1.8 6.05
2.0 7.39


        Divided Difference Table:
=================================================================
i x(i) f(i) f(i,i+1) f(i,i+1.i+2),  ......

{0} {1.00000} {2.72000} {3.00000} {1.75000} {-0.16667} {2.11806} {-3.29861}

{1} {1.20000} {3.32000} {3.70000} {1.66667} {1.52778} {-1.18056}

{2} {1.40000} {4.06000} {4.20000} {2.58333} {0.58333}

{3} {1.50000} {4.48000} {5.23333} {2.93333}

{4} {1.80000} {6.05000} {6.70000}

{5} {2.00000} {7.39000}

>>> 

寫出 i=2到i=5 的一元三次方程式
P(x) = 4.06 + 4.2 (x-1.4) + 2.58333 (x-1.4)(x-1.5) + 0.58333 (x-1.4)(x-1.5)(x-1.8)

沒有留言:

張貼留言

2024產專班 作業2

 2024產專班 作業2   1. 系統圖       ESP32+MFRC522 組成RFID Reader 可以將RFID卡片的UID 透過 MQTT協定    上傳(發行 主題 (:topic) alex9ufo/2024/RFID/RFID_UID  ,, Payload...