習題1-1-b
利用Lagrange內差法寫出下面諸點的方程式
P9x)= a0 + a1x + a2 x^2 + a3 x^3 + a4 x^4 + ......an x^n
Python程式
'''
n=4
xa=[-2.5 , -2.2 .-1.5 ,0.5 , 1.5 , 2.2 ]
-2.0 0.00
-1.0 4.00
0.0 0.00
1.0 -6.00
2.0 -8.00
/* pr1-1-b.py : Lagrange Interpolation Algorithm
* Read in data file of ex1-4.dat which has n point values
* and the value of interpolating point xa. Based on Lagrange
* Interpolation algorithm to compute p(xa) and output its value.
* (x[i],f[i]):given points and n+1 are number of points
* Ln,k(x)=l=summation of (x-x[i])/(x[k]-x[i]).
* p(x)=ff=L(x)*f(x[k])
*/
'''
import math
def fx(x):
return (math.pow(x,3)-math.pow(x,2) -6*x)
print('\nLagrange Interpolation Algorithm\n')
xa=[-2.5 , -2.2 ,-1.5 ,0.5 , 1.5 , 2.2 ]
x=[-2.0 , -1.0 , 0.0 , 1.0 , 2.0 ]
f=[0.0 , 4.0 , 0.0 , -6.0 , -8.0 ]
n=4 # 5 point n=4
print('x=',x)
print('f=',f)
print('xa=',xa)
print('\n')
for m in range (len(xa)):
indata=xa[m]
result=0.0
print("xa=",repr(indata))
for k in range (0,n+1): #n -->n+1
temp=1.0;
for i in range (0,n+1): #n -->n+1
if(i !=k):
temp=temp * ( indata - x[i]) / ( x[k] - x[i])
result = result + temp *f[k]
s1 = 'The value of p' + repr(indata) + '= ' + repr(result) + ' ...'
print(s1)
resultfx=fx(indata)
s1 = 'The value of f(' + repr(indata) + ')= ' + repr(resultfx) + ' ...'
print(s1)
s1 = 'The value of | f(' + repr(indata) + ') - p' + repr(indata) + ' = ' + repr( abs(resultfx - result) ) + ' ...'
print(s1)
print("\n\n")
輸出畫面
======== RESTART: H:/2018-09勤益科大數值分析/數值分析/PYTHON/pr1-1-b.py ==========
Lagrange Interpolation Algorithm
x= [-2.0, -1.0, 0.0, 1.0, 2.0]
f= [0.0, 4.0, 0.0, -6.0, -8.0]
xa= [-2.5, -2.2, -1.5, 0.5, 1.5, 2.2]
xa= -2.5
The value of p-2.5= -6.875 ...
The value of f(-2.5)= -6.875 ...
The value of | f(-2.5) - p-2.5 = 0.0 ...
xa= -2.2
The value of p-2.2= -2.2880000000000025 ...
The value of f(-2.2)= -2.288000000000002 ...
The value of | f(-2.2) - p-2.2 = 4.440892098500626e-16 ...
xa= -1.5
The value of p-1.5= 3.375 ...
The value of f(-1.5)= 3.375 ...
The value of | f(-1.5) - p-1.5 = 0.0 ...
xa= 0.5
The value of p0.5= -3.125 ...
The value of f(0.5)= -3.125 ...
The value of | f(0.5) - p0.5 = 0.0 ...
xa= 1.5
The value of p1.5= -7.875 ...
The value of f(1.5)= -7.875 ...
The value of | f(1.5) - p1.5 = 0.0 ...
xa= 2.2
The value of p2.2= -7.391999999999999 ...
The value of f(2.2)= -7.391999999999999 ...
The value of | f(2.2) - p2.2 = 0.0 ...
>>>
訂閱:
張貼留言 (Atom)
113 學年度第 1 學期 RFID應用課程 Arduino程式
113 學年度第 1 學期 RFID應用課程 Arduino程式 https://www.mediafire.com/file/zr0h0p3iosq12jw/MFRC522+(2).7z/file 內含修改過後的 MFRC522 程式庫 (原程式有錯誤) //定義MFRC522...
-
python pip 不是内部或外部命令 -- 解決方法 要安裝 Pyqt5 1. 首先,開啟命令提示字元。 2. 輸入 pip3 install pyqt5 好像不能執行 ! ! 錯誤顯示 : ‘ pip3 ’ 不是內部或外部命令、可執行的程式或批...
-
課程講義 下載 11/20 1) PPT 下載 + 程式下載 http://www.mediafire.com/file/cru4py7e8pptfda/106%E5%8B%A4%E7%9B%8A2-1.rar 11/27 2) PPT 下載...
-
• 認 識 PreFix、InFix、PostFix PreFix(前序式):* + 1 2 + 3 4 InFix(中序式): (1+2)*(3+4) PostFix(後序式):1 2 + 3 4 + * 後 序式的運算 例如: 運算時由 後序式的...
沒有留言:
張貼留言