習題1-1-d
根據下面的已知點撰寫Lagrange 內差法程式
並計算 xa=[150 ,250 ,350 ,450 ,550 , 650 ]之值
'''
n=5
x= [100, 200, 300 ,400, 500 ,600]
f(x)=[1700 , 1000 ,833 , 800 ,820 , 867]
xa=[150 ,250 ,350 ,450 ,550 , 650 ]
/* pr1-1-b.py : Lagrange Interpolation Algorithm
* Read in data file of ex1-4.dat which has n point values
* and the value of interpolating point xa. Based on Lagrange
* Interpolation algorithm to compute p(xa) and output its value.
* (x[i],f[i]):given points and n+1 are number of points
* Ln,k(x)=l=summation of (x-x[i])/(x[k]-x[i]).
* p(x)=ff=L(x)*f(x[k])
*/
'''
import math
def fx(x):
return (x + (160000/x))
print('\nLagrange Interpolation Algorithm\n')
x= [100, 200, 300 ,400, 500 ,600]
f=[1700 , 1000 ,833 , 800 ,820 , 867]
xa=[150 ,250 ,350 ,450 ,550 , 650 ]
n=5 # 6 point n=5
print('x=',x)
print('f=',f)
print('xa=',xa)
print('\n')
for m in range (len(xa)):
indata=xa[m]
result=0.0
print("xa=",repr(indata))
for k in range (0,n+1): #n -->n+1
temp=1.0;
for i in range (0,n+1): #n -->n+1
if(i !=k):
temp=temp * ( indata - x[i]) / ( x[k] - x[i])
result = result + temp *f[k]
s1 = 'The value of p' + repr(indata) + '= ' + repr(result) + ' ...'
print(s1)
resultfx=fx(indata)
s1 = 'The value of f(' + repr(indata) + ')= ' + repr(resultfx) + ' ...'
print(s1)
s1 = 'The value of | f(' + repr(indata) + ') - p' + repr(indata) + ' = ' + repr( abs(resultfx - result) ) + ' ...'
print(s1)
print("\n\n")
輸出畫面
====== RESTART: H:/2018-09勤益科大數值分析/數值分析/PYTHON/pr1-1-d.py ==========
Lagrange Interpolation Algorithm
x= [100, 200, 300, 400, 500, 600]
f= [1700, 1000, 833, 800, 820, 867]
xa= [150, 250, 350, 450, 550, 650]
xa= 150
The value of p150= 1238.8242187499998 ...
The value of f(150)= 1216.6666666666667 ...
The value of | f(150) - p150 = 22.15755208333303 ...
xa= 250
The value of p250= 885.34765625 ...
The value of f(250)= 890.0 ...
The value of | f(250) - p250 = 4.65234375 ...
xa= 350
The value of p350= 809.18359375 ...
The value of f(350)= 807.1428571428571 ...
The value of | f(350) - p350 = 2.0407366071428896 ...
xa= 450
The value of p450= 803.2070312500001 ...
The value of f(450)= 805.5555555555555 ...
The value of | f(450) - p450 = 2.3485243055554292 ...
xa= 550
The value of p550= 846.79296875 ...
The value of f(550)= 840.909090909091 ...
The value of | f(550) - p550 = 5.883877840909008 ...
xa= 650
The value of p650= 842.81640625 ...
The value of f(650)= 896.1538461538462 ...
The value of | f(650) - p650 = 53.33743990384619 ...
>>>
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