Python: Input an integer (n) and computes the value of n+nn+nnn

Python Basic: Exercise-10 with Solution

Write a Python program that accepts an integer (n) and computes the value of n+nn+nnn.

Sample value of n is 5

Python int(x, base=10):

The function returns an integer object constructed from a number or string x, or return 0 if no arguments are given. If x is a number, return x.__int__(). For floating point numbers, this truncates towards zero.

• If x is not a number or if base is given, then x must be a string, bytes, or bytearray instance representing an integer literal in radix base
• The literal can be preceded by + or - (with no space in between) and surrounded by whitespace
• A base-n literal consists of the digits 0 to n-1, with a to z (or A to Z) having values 10 to 35. The default base is 10.
• The allowed values are 0 and 2-36. Base-2, -8, and -16 literals can be optionally prefixed with 0b/0B, 0o/0O, or 0x/0X, as with integer literals in code.

Sample Solution :-

a = int(input("Input an integer n : "))

n1 = int( "%s" % a )

n2 = int( "%s%s" % (a,a) )

n3 = int( "%s%s%s" % (a,a,a) )

print(n1)

print(n2)

print(n3)

print('n+nn+nnn = ' ,end='')

print (n1+n2+n3)

=========== RESTART: F:/Python_APSC/py-ex-basic-10.py ============

Input an integer n : 7

7

77

777

n+nn+nnn = 861

>>>