2018年12月23日 星期日

DEV C++ 牛頓內插法 建立差除表

DEV C++ 牛頓內插法 建立差除表  EX1-9  P1-38
C++   Code 



// CPP program for implementing
// Newton divided difference formula
#include <bits/stdc++.h>
using namespace std;

// Function to find the product term
float proterm(int i, float value, float x[])
{
float pro = 1;
for (int j = 0; j < i; j++) {
pro = pro * (value - x[j]);
}
return pro;
}

// Function for calculating
// divided difference table
void dividedDiffTable(float x[], float y[][10], int n)
{
for (int i = 1; i < n; i++)
{
  for (int j = 0; j < n - i; j++)
y[j][i] = (y[j][i - 1] - y[j + 1] [i - 1]) / (x[j] - x[i + j]);
}
}

// Function for applying Newton's
// divided difference formula
float applyFormula(float value, float x[],
float y[][10], int n)
{
float sum = y[0][0];

for (int i = 1; i < n; i++) {
sum = sum + (proterm(i, value, x) * y[0][i]);
}
return sum;
}

// Function for displaying
// divided difference table
void printDiffTable(float y[][10],int n)
{
for (int i = 0; i < n; i++) {
for (int j = 0; j < n - i; j++) {
cout << setprecision(4) <<
y[i][j] << "\t ";
}
cout << "\n";
}
}

// Driver Function
int main()
{
// number of inputs given
int n = 6;
float value, sum, y[10][10];
float x[] = { 0, 0.1, 0.3, 0.6 , 1.0 , 1.1 };

// y[][] is used for divided difference
// table where y[][0] is used for input
y[0][0] = -6;
y[1][0] = -5.89483;
y[2][0] = -5.65014;
y[3][0] = -5.17788;
y[4][0] = -4.28172;
y[5][0] = -3.99583;


// calculating divided difference table
dividedDiffTable(x, y, n);

// displaying divided difference table
printDiffTable(y,n);

// value to be interpolated
value = 0.8;

// printing the value
cout << "\nValue at " << value << " is "
<< applyFormula(value, x, y, n) << endl;
return 0;
}

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